Question

The mass of the earth is 6 x 10 kg.
The distance between the earth and
the Sun is 1.5x 101 m. If the
gravitational force between the two
is 3.5 x 1022 N, what is the mass of
the Sun?​

Answer 1

Answer:the mass of the earth, m = 6 × 10²⁴ kg

Assume the mass of the sun is M

distance between earth and sun , r = 1.5 × 10¹¹ m

force between sun and earth , F = 3.5 × 10²² N

use gravitational force formula,

F = GMm/r²

3.5 × 10²² = 6.67 × 10⁻¹¹ × 6 × 10²⁴ M/(1.5 × 10¹¹)²

3.5 × 10²² × 2.25 × 10²²/(6.67 × 6 × 10¹³) = M

M = 0.196 × 10³¹ kg

hence, mass of the sun is 1.96 × 10³⁰ kg

Explanation: plzz mark as brainliest if helps u

Answer 2

Given:

• The mass of the Earth is 6 × 10²⁴ kg
• The distance between the Earth and Sun is 1.5 × 10¹¹ m
• The Gravitational Force between the two is 3.5 × 10²² N

Answer:

$:\implies \sf F = \dfrac{G m_1 m_2}{r^2}$

$:\implies \sf 3.5 \times 10^{22} = \dfrac{(6.7 \times 10^{-11}) \times (6 \times 10^{24} )\times m_2}{(1.5 \times 10^{11})^2}$

$:\implies \sf 3.5 \times 10^{22} = \dfrac{6.7 \times 6 \times 10^{13} \times m_2}{1.5^{2} \times 10^{22}}$

$:\implies \sf 3.5 \times 10^{22} = \dfrac{6.7 \times 6 \times m_2}{1.5^{2} \times 10^{9}}$

$:\implies \sf 3.5 \times 10^{31} = \dfrac{6.7 \times 6 \times m_2}{1.5^{2} }$

$:\implies \sf m_{2} = \dfrac{3.5 \times {10}^{31} \times 2.25}{40.2 } \: kg$

$:\implies \sf m_{2} = \dfrac{78.75 \times {10}^{30} }{40.2 } \: kg$

$:\implies \underline{ \boxed{ \sf m_{2} = 1.96 \times {10}^{30} \: kg}}$

$\therefore \underline{\sf The \:mass\: of\: the\: sun\: is \:1.96 \times {10}^{30} \: kg}.$