Question

the mass of the mars is 6.39 ×10 ^22 kg and that of the Jupiter is 189×10^27kg . if the distance is 749×10^3 m find the exerted force produced by Jupiter on mars g is 6.7 ×10^-11 NM ^2 kg^-2​

Answer 1

$\begin{gathered} {\huge\underline{\underline{\text{Solution:}}}} \\ \end{gathered}$

$\sf Given \: the \: mass \: of \: the \: mars \: Mm = 639 \times 10 {}^{23} kg$

$\sf \: the \: mass \: of \: the \: jupiter \: Mj \: = 1.89 \times 10 {}^{27} kg$

$\sf \: the \: distance \: between \: mars \: and \: jupiter = \\ F = G \frac{M.m \times M.j}{d {}^{2} } \\ \\ = \frac{6.7 \times 10 {}^{ - 11 } \times 6.39 \times 10 {}^{23} \times 1.89 \times 10 {}^{27} }{(7.49 \times 10 { }^{5}) {}^{2} } \\ \\ = 1.44 \times 10 {}^{29} N \\ \\ \\ \longmapsto\tt{Thus \: the \: force \: exerted \: by \: the \: }jupiter \: on \: the \: mars \: is \\ \longmapsto{ = 1.44 \times 10 {}^{29} }N$

Note :-

• please Split the Page To see more Answers on This page ..

Answer 2

Answer:

Hi Yuki it's me Adeline.. how are you? hope you're doing well.. I am just doing alright.. going on with 12th std.. take care love you❤