Question

The mass of the moon is 7.36×1022kg and its distance to the Earth is 3.84×108m.
What is the gravitational force of the moon on the earth?

Answer 1

Answer:

Explanation:

Using Newton's gravitational force equation

F

=

G

m

1

m

2

r

2

and assuming that the mass of the Earth is

m

1

=

5.972

⋅

10

24

k

g

and

m

2

is the given mass of the moon with

G

being

6.674

⋅

10

−

11

N

m

2

(

k

g

)

2

gives

1.989

⋅

10

20

k

g

m

s

2

for

F

of the moon.

Repeating this with

m

2

as the mass of the sun gives

F

=

5.375

⋅

10

27

k

g

m

s

2

This gives the moon's gravitational force as

3.7

⋅

10

−

6

%

of the Sun's gravitational force.

Explanation:

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Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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