Question

the mass of two objects are 4×10 24kg and 3 ×10 20 kg respectively they are separated by the distance of 3 × 10 -8 calculate the gravitational force of attraction between these two objects (G=6.67×10 -11Nm2/kg2)​

Answer 1

Given :-

• The mass of first object {(m_(1)} = 4 × 10²⁴ kg
• The mass of second object {(m_(2)} = 3 × 10²⁰ kg
• The distance between the objects {R} = 3 × 10-⁸m
• Gravitational force (G) = 6.67 × 10-¹¹ m²/kg²

To Find :-

• Gravitational force between two objects = ?

Solution :-

To calculate the gravitational force between two objects at first we have to apply formula then substitutes the value which is obtained from the given Question.

Formula Used :-

⇢ F = (G × m_1 × m_2)/R

• F = gravitational force between two objects.

⇢ F = (6.67 × 10-¹¹ × 4 × 10²⁴ × 3 × 10²⁰)/3 × 10-⁸

⇢ F = 6.67 × 4 × 3 × 10^(24 + 20 - 11) /3 × 10-⁸

⇢ F = 6.67 × 12 × 10³³/3 × 10-⁸

⇢ F = (80.04 × 10³³ × 10⁸)/3

⇢ F = 80.04 × 10²⁵/3

⇢ F = 26.68 × 10²⁵

⇢ F = 2.668 × 10²⁴ N

Hence, gravitational force between two objects = 2.668 × 10²⁴N

Answer 2

$\rm\huge\underline\pink{Given:-}$

$\tt{\rightarrow 1st\: object\:mass\:(m_1)= 4 * 10^24 kg}$

$\tt{\rightarrow 2nd\: object\:mass\:(m_2)= 3 * 10^{20}kg}$

$\tt{\rightarrow Object\: distance (R)= 3 * 10^{-8}m}$

$\rm\huge\underline\pink{To\:Gain:-}$

$\tt{\rightarrow Gravitational\: Force\:of\: attraction}$

$\rm\huge\underline\pink{Solution:-}$

$\sf{\longrightarrow F = \dfrac{(G\:m_1\:m_2)}{R}}$

$\sf{\longrightarrow F = \dfrac{6.67*10^{-11}*4*10^{24}*3*10^{20}}{3*10^{-8}}}$

$\sf{\longrightarrow F = \dfrac{80.04* 10^{25}}{3}}$

$\sf{\longrightarrow F = 26.68*10^{25}}$

$\sf{\longrightarrow F = 2.668*10^{24}N}$

$\sf\small\underline\green{gravitational\: force\: attraction=2.668*10^{24}N}$