the mass of two objects are 4×10^24kg and 3 ×10^20 kg respectively they are separated by the distance of 3 × 10 ^8 calculate the gravitational force of attraction between these two objects (G=6.67×10 ^-11Nm2/kg2)
Answers
Given :-
The mass of first object {(m_(1)} = 4 × 10²⁴ kg
The mass of second object {(m_(2)} = 3 × 10²⁰ kg
The distance between the objects {R} = 3 × 10-⁸m
Gravitational force (G) = 6.67 × 10-¹¹ m²/kg²
To Find :-
Gravitational force between two objects = ?
Solution :-
To calculate the gravitational force between two objects at first we have to apply formula then substitutes the value which is obtained from the given Question.
Formula Used :-
⇢ F = (G × m_1 × m_2)/R
F = gravitational force between two objects.
⇢ F = (6.67 × 10-¹¹ × 4 × 10²⁴ × 3 × 10²⁰)/3 × 10-⁸
⇢ F = 6.67 × 4 × 3 × 10^(24 + 20 - 11) /3 × 10-⁸
⇢ F = 6.67 × 12 × 10³³/3 × 10-⁸
⇢ F = (80.04 × 10³³ × 10⁸)/3
⇢ F = 80.04 × 10²⁵/3
⇢ F = 26.68 × 10²⁵
⇢ F = 2.668 × 10²⁴ N
Hence, gravitational force between two objects = 2.668 × 10²⁴N
Answer:
Explanation:
Given :-
The mass of first object {(m_(1)} = 4 × 10²⁴ kg
The mass of second object {(m_(2)} = 3 × 10²⁰ kg
The distance between the objects {R} = 3 × 10-⁸m
Gravitational force (G) = 6.67 × 10-¹¹ m²/kg²
To Find :-
Gravitational force between two objects = ?
Solution :-
To calculate the gravitational force between two objects at first we have to apply formula then substitutes the value which is obtained from the given Question.
Formula Used :-
⇢ F = (G × m_1 × m_2)/R
F = gravitational force between two objects.
⇢ F = (6.67 × 10-¹¹ × 4 × 10²⁴ × 3 × 10²⁰)/3 × 10-⁸
⇢ F = 6.67 × 4 × 3 × 10^(24 + 20 - 11) /3 × 10-⁸
⇢ F = 6.67 × 12 × 10³³/3 × 10-⁸
⇢ F = (80.04 × 10³³ × 10⁸)/3
⇢ F = 80.04 × 10²⁵/3
⇢ F = 26.68 × 10²⁵
⇢ F = 2.668 × 10²⁴ N
Hence, gravitational force between two objects = 2.668 × 10²⁴N