Question

The mass of water 300g the temperature 30 ° C is heated so that it becomes a whole steam. Caloric water type 1000J / kg ° C, steam heat 227000J / ° C. What is the amount of heat needed?

Answer 1

Known:

m = 300 gr = 0.3 kg

To = 30 C

c water = 1000 J / KgC

U = 227,000 J / Kg

Asked: Q?

Answered:

Q1 = m x c x (T-To)

= 0.3 x 1000 x (100-30)

= 0.3 x 1000 x 70

= 21,000 J

Q2 = m x U

= 0.3 x 227,000

= 68,100 J

So the required heat = 21000 + 68100 = 89,100 J