the mass of water when 4.6g of sodium reacts completely with excess water [ Na =23, H =1 , O=16]
Answers
Answered by
0
Answer : 2240 mL
2Na+2H2O2×23=46g→2NaOH+H222400mL
46 g of Na evolve hydrogen at N.T.P = 22400 mL
4.6 g of Na evolve hydrogen at N.T.P =22400×4.646=2240mL.
Similar questions