The mass of Zn required to produce 2240 ml of H₂ at STP on treatment with dilute H₂SO4 will be (Zn = 65.3) Zn + H₂SO4 →→→ ZnSO4 + H₂
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csn to get the question properly
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By observing the equation,
22.4L=22400ml of H2 produced by 65.3gm Zn
1ml ″ H2 ″ ″ = 65.3/22400 gm of Zn
2240ml of H2 produced by 65.3/22400×2240gm Zn
=6.53gm Zn required
6.53 gm is the answer.
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