The mass percent of NO3 in ca(NO3)2 ( atomic mass N= 22, O = 16, Ca = 40) is
Answers
Answered by
1
Explanation:
Molar mass of Ca ( NO3 ) 2 = 40 + ( 14 + 48 )2= 40 + 124 = 164
Required percentage = 124/164 × 100 = 75.06
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Answered by
1
Answer:
hello mate,
Explanation:
mass percent of No³ is 70/180*100
7/18*100=0.338×100
338 is the answer....
hope u will understand...
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