Question

the mass percentage composition of a substance is 24.7% Ca,1.24% H,14.8% C and 59.3% O . Calculate the molecular formula of the substance if its molecular mass is 162 u.​

Answer 1

Answer:

Explanation:

Ca=24.7/40

H=1.24/1

C=14.8/12

O=59.3/16

CA=1

H=1.24*40/24.7=2

C=14.8/12*40/24.7=2

O=59.3/16*40/24.7=6

SO........CaH2C2O6 EMPIRICAL FORMULA

162/162=1

CaH2C2O6*1=CaH2C2O6 MOLECULAR FORMULA