The mass percentage of a sugar in a solution containing 47g of sugar and 72g of water is
Answers
According to the question,
Mass of solute ( sugar ) = 20 g
Mass of solvent ( water ) = 80 g
Mass of the solution = Mass of solute + Mass of solvent = 36 + 100 = 136 g
We know,
Concentration of solution =
Mass of solute / (Mass of solute + Mass of solvent) X 100
= {20 / ( 20+80 )} X 100
= (20 / 100) x 100
= 20 %
Thus, the concentration of this sugar solution is 20 % ( by Mass )
Given,
Mass of Sugar = 47 g
Mass of Water = 72 g
To find,
The mass percentage of a sugar
Solution,
Mass of Sugar ( Solute ) = 47 g
Mass of Water ( Solvent ) = 72 g
The mass percentage of a sugar = ?
As We know that,
The mass percentage of solution = (Mass of solute/ Mass of solution) X 100
⇒ Mass of solution = Mass of solvent + Mass of solute
⇒ Mass of solution = 72g + 47g = 119g
The mass percentage of the solution = (Mass of solute / Mass of solution) X 100
The mass percentage of the solution = (47g / 119g) X 100
The mass percentage of the solution = 39.49%
Hence, mass percentage of sugar is 39.49%