Question

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)(a) 28.4 MeV(b) 20.8 MeV
(c) 27.3 MeV(d) 14.2 MeV

Answer 1

I THINK THE ANSWER SHOULD BE b 20.8MeV

Answer 2

Answer:

28.4

Explanation:

• 2×1.008=2.016 + 2×1.007=2.014 =4.03 . 4.03- 4.0015 = approx 0.03 × 931ev =approx 28 something. so right answer will ne a. thanks. best of luck