The masses of three wires of copper are in the ratio 1:3:5 and their lengths are in the ratio 5:3:1. Then
the ratio of their electrical resistance are:
1) 1:3:5
2) 5:3:1
3) 1:15:25
4) 125:15:1
Answers
Answered by
3
Answer:
hope it helps u
Explanation:
Resistance of a wire is given as
A
ρL
This is the same as
A×L
ρL
2
=
V
ρL
2
So, resistance is proportional to
M
L
2
The ratio of resistances is,
1
25
:
3
9
:
5
1
=125:15:1
Answered by
2
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