Math, asked by okwakye123, 11 months ago

The math club is electing new officers. There are 3 candidates for president, 4 candidates for vice-president, 4 candidates for secretary, and 2 candidates for treasurer. How many different combinations of officers are possible?

Answers

Answered by elliekochneva
6

Answer:

There should be 96 different combinations possible

Step-by-step explanation:

Answered by panashekadzunge8
0

Answer: 96

3C1 X 4C1 X 4C1 X 2C1

Step-by-step explanation:

There are 4 candidates that must be recruited from the possible 13 so for each department 1 must be picked.

so use the calculator combination function

3C1 ( 3 choose 1)

Similar questions