the maximim value of 5sinx+3cosx
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take that X = 90° because maximum value
sin90° = 1. cos90° = 0
5(sin90°)+3(cos90°)
= 5(1)+3(0)
= 5 +0
= 5
so the maximum value of 5sinx +3cosx is 5
sin90° = 1. cos90° = 0
5(sin90°)+3(cos90°)
= 5(1)+3(0)
= 5 +0
= 5
so the maximum value of 5sinx +3cosx is 5
SanskarGupta091:
your answer is correct
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3sinx-4 cos x =+✓(3 sq+4 sq)=✓25.=5
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