Question

. The maximum acceleration of a particle executing simple
harmonic motion is 0.296 m.s-2; its time period is 2 s and
the displacement from the equilibrium position at the
beginning of its motion is 0.015 m. Determine the equation
of motion of the particle.
(Ans.
Ans. x =
x = 0.03 cost +
T)​

Answer 1

Answer:

Sorry everyone

Not know