Question

The maximum acceleration of a particle performing SHM is 6m/s^2 and its period is 6.28sec. Find
1.Amplitude
2.velocity when displacement is 3cm.
3.Acceleration when the velocity is 4m/s.
pls answer me​​...​

Answer 1

Answer:

For SHM,

v=ω

A

2

−x

2

Given:

13=ω

A

2

−3

2

(i)

12=ω

A

2

−5

2

)

(ii)

Eliminating A, we get:

ω

2

13

2

+3

2

=

ω

2

12

2

+5

2

ω=

4

5

f=

8π

5

H