Question

the maximum acceleration the accelerator gives and the maximum retardation the brake can give is 5m/s^2 the maximum distance the car can complete when starts from rest with in 1 minute just before it comes to rest.

Answer 1

Answer:

(alpha×Beta/alpha+Beta) be the accl, so a=2.5m/s^2.

S=1/2at^2, so s=4500 km

Answer 2

HEYA MATE YOUR ANSWER IS

So −v=−10(T−t)-------(B)

Putting the value of A in B we get

−5t=−10T+10t

T=

2

3t

-------(C)

As the total distance covered by the motorcycle in T seconds=1500 m,

thus

2

1

vT=1500

vT=3000

As earlier found v=5t and T=

2

3t

5t

2

3t

=3000

t

2

=400

t=20s

we know T=

2

3t

T=30s

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