Physics, asked by zabiullah12234, 9 months ago

The maximum & minimum value of y = x + 1/x in interval [1/3, 4/3](1) 2,-2(2) 10/3,2 (4) None of these​

Answers

Answered by gadakhsanket
7

Hello Students,

◆ Answer -

(2) 10/3, 2

◆ Explanation -

Given function -

y = x + 1/x

This function can be defined for all numbers except x = 0 as y -> infinity. But x = 0 doesn't appear in closed interval [1/3, 4/3], so that doesn't concern here.

Maximum value is at x = 1/3,

y = x + 1/x

y = 1/3 + 3

y = 10/3

Minimum value is at x = 1,

y = x + 1/x

y = 1 + 1

y = 2

Therefore, maximum and minimum values of y are 10/3 and 2 respectively.

Thanks dear..

Similar questions