Question

The maximum amplitude of an AM wave is found to be 15 V while its minimum amplitude is found to be 3 V.What is the modulation index?

Answer 1

Answer:

Explanation:

Modulation index μ,

=Amax−AminAmax+Amin

(A = amplitude of modulated wave)

∴μ=15−315+3=1218=23.

Answer 2

Given:

1. Maximum amplitude of an AM wave is 15 V
2. Minimum amplitude of the AM wave 3 V.

To find:

1. The modulation index

Answer:

1. We know that the modulation index of a wave is $\frac{Amax - A min}{Amax + Amin}$
2. The modulation index = 15-3 / (15+3) = 12/18 = 2/3 = 0.667

Thus the modulation indev of the AM wave is 0.667