The maximum and minimum magnitude of resultant of two vectors are 12 units and 6 units respectively. Then the magnitudes of two vectors will be
Answers
Answer:
Correct option is
D
13
Step 1: Equation for resultant of two vectors
Let θ be the angle between the vectors
A
and
B
The resultant of two vectors is given by
R=
A
2
+B
2
+2ABcosθ
For R
max
,θ=0
∘
⇒∣
R
max
∣=∣
A
∣+∣
B
∣
⇒17=∣
A
∣+∣
B
∣ ....(1)
For R
min
,θ=180
∘
⇒∣
R
min
∣=∣
A
∣−∣
B
∣
⇒7=∣
A
∣−∣
B
∣ ....(2)
Step 2: Calculation of Magnitude of
A
and
B
Adding equation (1) and (2) ⇒2∣
A
∣=24
⇒
A
=12
From equation (1)⇒ ∣
B
∣=5
Step 3: Calculation of R when vectors are perpendicular
∵
A
⊥
B
∣
R
∣=
A
2
+B
2
+2ABcos90
o
⇒∣
R
∣=
12
2
+5
2
=
169
units
⇒∣
R
∣=13 units
Hence the magnitude of resultant vector is 13 units. Option D is correct.
Answer:
The magnitude of vector A is equal to 12 units and the magnitude of vector B is equal to 3 units.
Explanation:
Given, the maximum magnitude of resultant vector, = 12 units
The minimum magnitude of resultant vector, = 6 units
Consider that θ is the angle between two vectors A and B:-
Then the resultant vector can be determined as-
When θ = 0°, the maximum magnitude of resultant vector will be given by:-
...................(1)
When θ = 180°, the minimum magnitude of resultant vector will be given by:-
...................(2)
Add the equation (1) and (2);
Substitute the value of magnitude of a in equation (1);
Therefore, the magnitude of vector A is equal to 12 and the magnitude of B is equal to 3.
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