Question

The maximum and minimum resultant of two fores are in the ratio 7:3 . The ratio of the forces is

Answer 1

Answer:

Explanation:R maximum=(A+B)=7------eq^n(1)

R minimum=(A-B)=3------eq^n(2)

From eq^n (1) &(2)

A+B=7

A-B=3

———

2A=10

A=10/2

A=5

Putting the value of A in eq^n(1)

5+B=7

B=7-5

=2

Now,

According to the question. The ratio of forces be

A/B= 5:2

Hope it will help you....

Answer 2

Given:

• The maximum and minimum resultant of two fores are in the ratio 7:3.

To find:

• Ratio of individual forces ?

Calculation:

• Maximum resultant of two forces occur when the two forces at directed towards the same side and parallel to one another. In that case F_(max) = F1 + F2.

• Minimum resultant of two forces occur when the two forces are directed towards opposite side and parallel to one another. In that case F_(min) = F1 - F2.

$\dfrac{F_{max}}{F_{min}} = \dfrac{7}{3}$

$\implies \dfrac{F1 +F2 }{F1 -F2 } = \dfrac{7}{3}$

$\implies 3F1 +3F2 = 7F1 -7F2$

$\implies (3 + 7)F2 = (7 - 3)F1$

$\implies( 10)F2 = (4)F1$

$\implies\dfrac{F1}{F2} = \dfrac{10}{4}$

$\implies\dfrac{F1}{F2} = \dfrac{5}{2}$

So, the ratio of forces is 5 : 2 .