Question

the maximum and minimum temperature at place p are 32 degree Celsius and -3 degree Celsius respectively and another place Q the temperature are 30 degree Celsius and 2 degree Celsius respectively which place records a greater fall in temperature by how much​

Answer 1

The fall in temperature at place P is greater than at place Q by 7°C

Given:

• The maximum temperature at place P: 32°C
• The minimum temperature at place P: -3°C
• The maximum temperature at place Q: 30°C
• The minimum temperature at place Q: 2°C

To Find:

• Out of the two given places, which one has a greater fall in temperature and the magnitude of the fall

Solution:

• To figure out which one of the two places has a greater fall in temperature, we need to calculate the range of the temperature for  each of the two places and then compare the values
• Range is given by the formula: (Maximum Value)-(Minimum Value)
• This range is a measure of the fall in temperature for each place, in the given scenario

For place P:

        Fall in temperature= Maximum temperature-Minimum temperature

                                        = 32°C - (-3°C)

        Since the minimum value is a negative integer, the subtraction sign changes to a positive;

         ∴ Fall in temperature at place P= 32 + 3 °C

• Hence the fall in temperature at place P = 35°C

For place Q:

• Fall in temperature= Maximum temperature- Minimum temperature

                                       = 30°C- 2°C

• Hence fall in temperature at place Q= 28°C

The magnitude of fall of temperature at place P is > the magnitude of fall of temperature at place Q

The difference in the fall of temperature between places P and Q can be given by: Fall in temperature at place P- Fall in temperature at place Q

             = 35-28

             = 7°C

Hence, in conclusion, place P records a greater fall in temperature by 7°C

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