Question

The maximum and minimum temperatures at a place are (40.6 ± 0.3)deg C and (32.4 ± 0.2)deg C. Calculate the difference in the temperatures with error limits.

Answer 1

Answer:

$\boxed{\underline{\Huge{\mathtt{(8.2\pm0.5)^\circ C}}}}$

Explanation:

$\theta_1 = 40.6^\circ C; \:\:\:\:\:\:\:\:\:\:\:\:\:\: \Delta \theta_1 = 0.3^\circ C; \\  \theta_2=32.4^\circ C; \:\:\:\:\:\:\:\:\:\:\:\:\:\: \Delta\theta_2=0.2^\circ C; \:\:\:\:\:\:\:\:\:\:\:\:\:\: \theta=?\\\\\theta = \theta_1 - \theta_2 = 40.6-32.4 = 8.2^\circ C\\\\\Delta \theta = \pm(\Delta\theta_1 + \Delta\theta_2) = \pm(0.3 + 0.2)=\pm0.5^\circ C$

$\therefore \text{Difference in temperature with error limits } = (8.2\pm0.5)^\circ C$