Question

the maximum and minimum value of function F(X )= sin 3x + 4​

Answer 1

Answer:

Step-by-step explanation:

put dy/dx=0

3cos3x=0

cos 3x =0

cos 3x = cos 90

3x=2npi plus minus 90

x=2npi/3 plus minus 30

for one

x=2pi/3+30=150

x=2pi/3-30=90

d2y/dx2=-9sin3x

for x= 90

d2y/dx2=9

for x=150

d2y/dx2=0

isolated point

min value in interval {0 , 450} is 9

Answer 2

Answer:

12.....・゜゜・.・゜゜・.・゜゜・.・゜゜・