Question

The maximum area of a right angled triangle with hypotenuse h is:
(a) $\frac{h^{2}}{2\sqrt{2}}$
(b) $\frac{h^{2}}{2}$
(c) $\frac{h^{2}}{\sqrt{2}}$
(d) $\frac{h^{2}}{4}$

Answer 1

Hello mate ☺

Option A is correct one

Hope it helps u...❤

Answer 2

The maximum area of a right angled triangle with hypotenuse h is:

(a) $\frac{h^{2}}{2\sqrt{2}}$✔

(b) $\frac{h^{2}}{2}$

(c) $\frac{h^{2}}{\sqrt{2}}$

(d) $\frac{h^{2}}{4}$