Question

The maximum bending moment and torsion in a shaft of diameter
0.5 m is 20 kN-m and 15 kN m. Calculate the maximum shear
stress in the shaft in KPa.

Answer 1

Answer:

solve

Explanation:

plz check it again

Answer 2

Answer

Maximum shear stress formula

$shear \: stress \: = (16 \div \pi \times d {}^{3} ) \sqrt{m {}^{2} { + t}^{2} }$

Use the above formula

Put the value of d=0.5m, M=20000Nm and t =15000Nm we will get the value of

shear stress =

$(16 \div \pi(.5) {}^{3} ) \sqrt{20000 {}^{2} + 15000 {}^{2} }$

Shear stress= 101.9Mpa