Question

The maximum current that a 2w, 80 k resistor can safely conduct is:

Answer 1

The question is:

The maximum current that a 2W, 80 kΩ resistor can safely conduct is:

(a) 160 kA

(b) 40 kA

(c) 5 mA

(d) 25 μA

The correct option is c, i.e., 5 mA.

Given:

Power= P= 2W

Resistance= R= 80 kΩ= 80×1000 Ω= 80000 Ω

To find:

The maximum current that resistor can safely conduct.

Solution:

• Power the rate of change of work per unit time and resistance is the flow of current but in opposite direction.

The relation between power, resistance and current is:

P= I²R

I²= P/R

Now, put the value of P and R in the above equation,

I²= $\frac{2}{80000}$

I²= $\frac{1}{40000}$

I²= 0.000025

I= $\sqrt{0.000025}$

I= 0.005 A

I= 5 mA

Therefore, the correct option is c, i.e., 5 mA.

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