The maximum distance b/w the transmiting and receving tv tower is 72km .if the ratio of the height of the tv tranmitting tower to recoveing tower is 16:25 the height of the transmitting and receiving towers are
Answers
Answered by
0
Answer:
ANSWER
d
max
=
2RH
T
+
2RH
R
=72 km
H
R
H
T
=
25
16
⇒
25
2RH
R
×16
+
2RH
R
=72
⇒
5
4
2RH
R
+
2RH
R
=72
⇒(1+
5
4
)
2RH
R
=72⇒
2RH
R
=72(
9
5
)=40
⇒H
R
=125 mandH
T
=80 m
Similar questions