Question

The maximum growth yield coefficient for Bacillus subtilis growing on methanol is 0.4 g X/g S. The heat of combustion of cells is 21 kJ/g cells and for substrate it is 7.3 kcal/g. Determine the metabolic heat generated by the cells per unit mass of methanol consumption.

Answer 1

Answer:

Unsaturated hydrocarbons are more reactive due to the presence of C=C and C=C bonds which are weaker than the single bond in saturated hydrocarbons. These double and triple bonds are the reactive sites in the unsaturated hydrocarbons which easily give addition reactio

Answer 2

Answer:

2.21 KJ/g-substrate

Explanation:

Y x/s = 0.4 g-cell/g-substrate

var HC = ΔHc= 21 KJ/g-cell

var Hs = ΔHs = 30.5 KJ/g-substrate

Using:  

var Hs / Y x/s = var Hc + 1/Yh

1/Yh = 55.25 kj/g-cells

Using Yx/s:

0.4g-cell - 1g-substrate

1g-cell - x

x = 25g-substrate

So, 55.25 KJ/g-cell ÷ 1g-cell/25g-substrate = 2.21 KJ/g-substrate