The maximum height attained by a projectile is
found to be equal to 0.423 of horizontal range.The
angle of projection of this projectile is
a)30° b)45° c)60° d)75°
Answers
Answered by
2
Answer:
According to question,
H=0.433R
2gu2sin2θ=0.433gu2sin2θ
sin2θ=2×0.433×2sinθ.cosθ
tanθ=4×0.433=1.732
θ=tan−1(1.732)=59.990
θ≈60
The correct option is C.
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