Question

The maximum height attained by projectile is 10 m and its horizontal range is 50 m. Calculate the angle
of projection and the time of flight.

Answer 1

Answer:

solved

Explanation:

H = u²sin²∝/2g

R = u²sin2∝/g

T = 2u sin∝/g

• H/R = 10/5 = tan∝/4 , tan∝ = 4/5 , ∝ = tan^-1(4/5) =

u²sin²∝ = 2gH = 200 ,

• T = 2u sin∝/g = 2√200/10 = 2√2 sec.