Question

The maximum height of a projactile is increand by 10%. by changing the angle of projection without changing the wem speed. The percentage increase in the time of flight is ?​

Answer 1

Answer:

don't know

Explanation:

hahah

Answer 2

Answer:

5% Approxx

4.88 %  ( to be More Precise)

Explanation:

The maximum height attained by a projectile is increased by 10%. Keeping the angle of projection constant,what is percentage increase in time of flight

Let say Velocity = V

Angle of Projection = α

Vertical Velocity = Vsinα

Time to reach max height = Vsinα/g

Time of Flight = 2Vsinα/g

Max height H =  V²/2g   => V = √(2gH)

=> Time of Flight  = 2√(2gH) sinα/g

=> Time of Flight ∝ √H

Now H is increased by 10 %

=> Time of Flight increased by = (1/2)10 = 5%  ( approx)

For Exact  calculation

Time of Flight  T = 2√(2gH) sinα/g  With Normal Height

when H is increased by 10 % => H = H + (10/100)H = 1.1H

Tn = 2√(2g*1.1H) sinα/g   = √1.1 T

(Tn - T)/T * 100

= (√1.1 T - T )/T * 100

= (√1.1  - 1)*100

= 4.88 %