Question

The maximum height of a projectile is half of its rangeon the horizontal .if the velocity of projectile is u.its range on the horizontal is

Answer 1

Answer:

Velocity at maximum height = half of initial velocity.

Velocity at maximum height = horizontal component.

V

x

=

2

u

⟹u

y

=

u

2

−

4

u

2

=

2

3

×u

i.e. tanθ=

3

θ=60

∘

Range of projectile =

g

u

2

sin2θ

=

g

u

2

sin120

∘

=

2g

3

u

2