Question

the maximum height reached by the projectille is 38 metre & The horizontal velocity at that instant is 32m/s. find the initial velocity of projection & angle of projection ​

Answer 1

Explanation:

h or distance traveled by object = 38m

v=32m/s

g (gravity)or a(acceleration )=9.8 m/s

we know that v^2-u^2=2as

32- u^2=2×9.8×38

u^2=744.8-32

u^2=712.8

u =26.7m/s

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