Question

The maximum horizontal range of a projectile is 400 m. The maximum value of height attained by it will be??

Answer 1

Answer:

100m

Explanation:

We know that Rmax=u^2/g

u^2=400×10

u^2=400m/s

Angle is 45 for max range

So H=(u^2×sin^2 theta)/2g

H=(4000×sin^2× 45)/2×10

By solving we get

H=100m

Answer 2

Answer:

⇒Rmax  =  u²/g= 400m (Forθ=45 p)

⇒ Hmax= u²/2g =400/2 = 200m (For θ=90°)

⇒200m