Question

. The maximum horizontal range of a projectile
on the earth is R. Then for the same velocity
of projection, its maximum range on another
planet is 5R/4. Then, ratio of acceleration due
to gravity on that planet and on the earth is
1) 5:4
2) 4:5 3) 25:16 4) 16:25
reply me solve it in a paper and sent me​

Answer 1

Answer:

2

Explanation:

At Earth hour is maximum when angle is 45° so

R = u^2/2g(e) ....(1)

At that planet,

5R/4 = u^2/2g(p)......(2)

Divide 1 by 2,

g(p)/g(e) = 4/5

Answer 2

Answer:

Explanation:

R MAX = U²/g

R = RANGE OF PROJECTION.

U = VELOCITY OF PROJECTION.

g = ACCELERATION DUE TO GRAVITY.

R MAX WHEN PROJECTED AT 45 DEGREE.

R EARTH ,R= U²/g₁..............(1)

R PLANET , 5R/4 = U²/g₂...................(2)

R /(5R/4) = U²*g₂/U²*g₁

4/5 = g₂/g₁

g₂/g₁= 4/5=4:5 .......[2].

HOPE THIS HELPS.