Question

the maximum horizontal range of is 4000m.what is its initial velocity​

Answer 1

Answer:

200m

Explanation:

Maximum horizontal range of a projectile is given by formula

R = $u^{2} /g$

4000= $u^{2}/ 10$

$u^{2} = 40000$

u= 200m

Answer 2

Answer:

search this in Google and see the book you donot come here for best explanation ask this to your teacher Have a nice day