Question

The maximum horizontal range, when a particle is projected with velocity `u` is 100m. what will be the range when particle is projected at an angle of 300 with the horizontal?

Answer 1

Here Q = 45 degree as thats the only angle where Range becomes max.

Here Rmax. =u square /4g
Calculate u from here

Then use R=u square sin2Q/g and put Q=30 degree
Substitute the values

Hope you get your answer.