Question

The maximum K.E found in alpha particle of natural origin is 77 Mev.
Find the closest distance of approach for the gold nucleus, (2-79 for
gold)
(Note: At closest distance of approach, kinetic energy is converted into
potential energy
3* 10-12 m
3x10-13 m
3x 10-14 m
3 x 10-15 m​

Answer 1

$3 \times {10}^{ - 12} \: m$