The maximum kinetic energy of a photoelectrons is 3eV. What is its stopping potential.?
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since KE max = eV
where V is stopping potential . so the V= KE(max) ÷ e
hence the answer should be 3 volt
nd to be more specific -3 volt because it is a negative potential
where V is stopping potential . so the V= KE(max) ÷ e
hence the answer should be 3 volt
nd to be more specific -3 volt because it is a negative potential
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