Question

the maximum kinetic energy of oscillating spring is 5 joules and its amplitude is 10 cm the force constant of the spring is.
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Answer 1

Answer:

The force constant of the spring is 1000 N/m

Explanation:

As we know that maximum kinetic energy of oscillating spring is given by the formula

$KE = \frac{1}{2}kA^2$

here we know that

$k =$spring constant

A = Amplitude

k = spring constant

here we know that maximum kinetic energy is 5 J and its amplitude is 10 cm

so we have

$5 = \frac{1}{2}k(0.10)^2$

$k = 1000 N/m$

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Topic : Oscillation of spring

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Answer 2

The force constant of the spring is 1000 N/m.

Explanation:

Given that,

The maximum kinetic energy of oscillating spring is 5 Joules

Amplitude of the oscillating spring, A = 10 cm = 0.1 m

To find,

The force constant of the spring.

Solution,

The maximum kinetic energy of the spring in terms of amplitude is given by :

$E=\dfrac{1}{2}kA^2$

$k=\dfrac{2E}{A^2}$

$k=\dfrac{2\times 5\ J}{(0.1\ m)^2}$

k = 1000 N/m

So, the force constant of the spring is 1000 N/m. Hence, this is the required solution.

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Oscillations in spring

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