the maximum kinetic energy of photoelectron eject from a potassium surface by ultraviolet light of wavelength 200nm is photoelectric thereshold wavelength for potassium is 440nm
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wavelength(λ) of UV light =188nm Energy of incident rays
= hc / λ (h=planks constant,c=speed of light)
= 1242eV−nm / 188nm
=6.606eV.
Threshold λ=230nm Threshold energy=work function
(Φ)= 1242eV−nm / 230nm
=5.4eV.
By Einstein photo-electric effect, Energy Incident =Φ+MaximumK.E. Thus the maximum kinetic energy of emitted electrons would be
=6.606−5.4=1.206eV.
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