Question

The maximum kinetic energy of photoelectron is found to be 6.63×10^-19J,when the metal irradiate with a radiation of frequency 2×10^15Hz. The threshold frequency of metal is abou

Answer 1

Hey Dear,

◆ Answer -

ν0 = 10^15 Hz

● Explaination -

# Given -

KE = 6.63×10^-19 J

ν = 2×10^15 Hz

# Solution -

Work done by the photoelectric process is given by -

W = Φ0 + KE

hν = hν0 + KE

hν0 = hν - KE

ν0 = ν - KE/h

Now substitute values,

ν0 = 2×10^15 - 6.63×10^-19 / 6.63×10^-34

ν0 = 2×10^15 - 10^15

ν0 = 10^15 Hz

Therefore, threshold frequency of the metal is 10^15 Hz.

Thanks dear...

Answer 2

Answer:

Up u go jjjjjjj=hjjjjjjjjjjj