Question

The maximum length of a pencil that can be kept in a rectangular box of dimension 8 cm*6 cm*2 cm is ??​

Answer 1

${\Huge{\underline{\underline{\mathfrak{\red{Solution:-}}}}}}$

Length of longest pencil,

= diagonal of the box

$= \sqrt{8 {}^{2} + 6 {}^{2} + 2 {}^{2} } = \sqrt{104}$

$= 2 \sqrt{26} cm$

Answer 2

Answer:

Length of longest pencil = diagonal of the box

$= \sqrt{ {8}^{2} + {6}^{2} + {2}^{2} } \\ = \sqrt{104} \\ = 2 \sqrt{26} \: cm$