Question

The maximum length of a pencil that can be kept in a rectangular box of dimensions 8 cm ✖ 6cm ✖ 2cm is

Answer 1

hope it will help you

Answer 2

According to the Question

Diagonal of box = ${\implies\sqrt{l^{2}+b^{2}+h^{2}}}$

l = 8cm

b = 6cm

h = 2cm

${\implies\sqrt{8^{2}+6^{2}+2^{2}}}$

${\implies\sqrt{64+36+4}}$

${\implies\sqrt{104}}$

${\implies 2\sqrt{26}}$