Question

The maximum length of a rod that can be kept in a cuboidal box of dimension 12cm x 9 cm x 8 cm is

Answer 1

Answer:

total surface area=2(length×breadth)+(breadth×height)+(height×length)

TSA=2(12×9)+(9×8)+(8×12)

TSA=2(108)+(72)+(96)

TSA=2(276)

TSA=552 ans

Answer 2

Answer:

17 cm

GIVEN:

l (length) = 12cm

b ( breadth) = 9cm

h ( height) = 8cm

To find:

The maximum length of a rod that can be kept in a cuboidal box of dimension 12cm x 9 cm x 8 cm .

SOLUTION:

$l = 12cm \\ \\ b = 9cm \\ \\ h = 8cm \\ \\ the \: maximum \: length \: of \: the \: rod \: is \: \: the \: \\ diagonal \: of \: cuboid. \\ \\ diagonal \: of \: cuboid \: = \sqrt{l {}^{2} + b {}^{2} + h {}^{2} } \\ \\ now \: putting \: the \: values \: we \: get \\ \\ \\ \\ = \sqrt{12 {}^{2} + 9 {}^{2} + 8 {}^{2} } \\ \\ = \sqrt{144 + 81 + 64} \\ \\ = \sqrt{289} \\ \\ = 17 \: cm \\ \\ the \: maximum \: length \: of \: rod \: = 17 \: cm$