Question

The maximum length of pencil that can be kept in a rectangular box of dimensions 12 cm × 9cm × 8 cm os

Answer 1

Length = 12 cm

Width = 9 cm

Height = 8 cm

Maximum length of pencil = Diagonal of box

= sqrt ( l^2 + b^2 + h^2)

= sqrt ( 12^2 + 9^2 + 8^2)

= sqrt ( 144 + 81 + 64)

= sqrt ( 289)

= 17 cm

Answer 2

✬ Length of pencil = 17 cm ✬

Step-by-step explanation:

Given:

• Length of rectangular box is 12 cm.
• Breadth of rectangular box is 9 cm.
• Height of rectangular box is 8 cm.

To Find:

• What will the maximum length of pencil that can be kept in this box ?

Solution: To find the maximum length of pencil we need to find the diagonal of the rectangular box or Cuboid.

★ Diagonal of Cuboid = √l² + b² + h² ★

• Putting the values on the formula •

$\small\implies{\sf }$ √12² + 9² + 8² cm

$\small\implies{\sf }$ √12 x 12 + 9 x 9 + 8 x 8 cm

$\small\implies{\sf }$ √144 + 81 + 64 cm

$\small\implies{\sf }$ √289 cm

$\small\implies{\sf }$ 17 cm

Hence, The length of pencil that can be kept will be of 17 cm.