the maximum no of electrons in an atom with quantum no n=3 ,l=2
Answers
Answer:Answer:
10 e
−
Explanation:
The idea here is that you must use the value of the angular momentum quantum number,
l
, which tells you the energy subshell in which an electron resides, to find the possible values of the magnetic quantum number,
m
l
.
The number of values that the magnetic quantum number can take tells you the number of orbitals that are present in a given subshell.
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So, you know that the magnetic quantum number depends on the value of the angular momentum quantum number
m
l
=
{
−
l
,
−
(
l
−
1
)
,
...
,
−
1
,
−
0
,
+
1
,
...
,
+
(
l
−
1
)
,
+
l
}
In your case, you have
l
=
2
, which is an accepted value for the angular momentum quantum number given the fact that the principal quantum number,
n
, is equal to
3
, so you can say that
m
l
=
{
−
2
,
−
1
,
−
0
,
+
1
,
+
2
}
This tells you that the
d
subshell, which is denoted by
l
=
2
, holds a total of
5
orbitals.
Since each orbital can hold a maximum of
2
electrons, one having spin-up and one having spin-down, you can say that you have
5
orbitals
⋅
2 e
−
1
orbital
=
10 e
−
Therefore, a maximum number of
10
electrons can share these two quantum numbers in an atom.
n
=
3
,
l
=
2
These electrons are located on the third energy level, in the
3
d
subshell
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