Question

the maximum no. of molecules is present in- (1) 15L of H2 gas at STP ​(2) 5L of N2 gas at STP ​(3) 0.5 g of H2 gas (4) 10 g of O2 gas

Answer 1

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➡ Option ( 1 ) is the correct answer - AS MOLES =15/22.4 
so moles =0.7 
& no. of molecules = moles × Na (avogadro no.)
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Answer 2

Answer:

The correct answer is option(1).

Explanation:

Moles=$\frac{\text{Mass of compound }}{\text{Molar mass of compound}}$

Number of molecules = $Moles \times N_A$

$N_A=6.022\times 10^{23} mol^{-1}$

Higher the number of moles more will be the molecules.

1) At STP, 1 mol of gas occupies 22.4 L of volume.

Then 15 L of volume will be occupied by:

$\frac{1}{22.4 L}\times 15 L=0.6696 mol$ of hydrogen gas

Molecules of hydrogen gas = $0.6696 mol\time N_A$

2) At STP, 1 mol of gas occupies 22.4 L of volume.

Then 5 L of volume will be occupied by:

$\frac{1}{22.4 L}\times 5 L=0.2232 mol$ of nitrogen gas

Molecules of nitrogen gas = $0.2232 mol\time N_A$

3) 0.5 g of H2 gas

Moles of hydrogen gas= $\frac{0.5 g}{2 g/mol}=0.2500 mol$

Molecules of hydrogen gas = $0.2500 mol\time N_A$

(4) 10 g of O2 gas

Moles of oxygen gas= $\frac{10 g}{32 g/mol}=0.3125 mol$

Molecules of oxygen gas =$0.3125 mol\times N_a$

Hydrogen gas with 0.6656 moles has highest number of hydrogen gas molecules.